A circle equation with a center different than (0,0,0)

[Terminator]

Hello,

I was checking this code (From this babylonJS tutorial: https://doc.babylonjs.com/tutorials/Ribbon_Tutorial)

var pi2 = Math.PI * 2;
var step = pi2 / 60;       // we want 60 points
for (var i = 0; i < pi2; i += step ) {
  var x = radius * Math.sin(i);
  var z = radius * Math.cos(i);
  var y = 0;
  path.push( new BABYLON.Vector3(x, y, z) );
  }
path.push(path[0]);       // to close the circle

it helped me to get points that belongs to the circumference of a circle with a specific radius, my question here is more mathematical, but I would appreciate if someone can help.

The above code assumes that the center of the circle is (0,0,0), how can I change the code in order to get the circle points assuming the center of the circle is (x1,0,z1) ?

[adam]

var ox = 0;
var oy = 0;
var oz = 0;

var pi2 = Math.PI * 2;
var step = pi2 / 60;       // we want 60 points
for (var i = 0; i < pi2; i += step ) {
  var x = radius * Math.sin(i) + ox;
  var z = radius * Math.cos(i) + oz;
  var y = oy;
  path.push( new BABYLON.Vector3(x, y, z) );
  }
path.push(path[0]);

 

[symof]

1 hour ago, Terminator said:

Hello,

I was checking this code (From this babylonJS tutorial: https://doc.babylonjs.com/tutorials/Ribbon_Tutorial)

var pi2 = Math.PI * 2;
var step = pi2 / 60;       // we want 60 points
for (var i = 0; i < pi2; i += step ) {
  var x = radius * Math.sin(i);
  var z = radius * Math.cos(i);
  var y = 0;
  path.push( new BABYLON.Vector3(x, y, z) );
  }
path.push(path[0]);       // to close the circle

it helped me to get points that belongs to the circumference of a circle with a specific radius, my question here is more mathematical, but I would appreciate if someone can help.

The above code assumes that the center of the circle is (0,0,0), how can I change the code in order to get the circle points assuming the center of the circle is (x1,0,z1) ?

http://www.tauday.com/

var ox = 0;
var oy = 0;
var oz = 0;

var tau = Math.PI * 2;
var step = tau / 60;       // we want 60 points
for (var i = 0; i < tau; i += step ) {
  var x = radius * Math.sin(i) + ox;
  var z = radius * Math.cos(i) + oz;
  var y = oy;
  path.push( new BABYLON.Vector3(x, y, z) );
  }
path.push(path[0]);

 

[Terminator]

hahaha @symof !! cool video

[Nabroski]

i just type 44 same thing, in most cases. saving bytes or not copy+paste #defines from somewhere( over and over again) makes me happy